6 is divisible by 1, 2, 3, and 6. 17 is prime. 25 is divisible by 1, 5 and 25. 36 is divisible by 1, 2, 3, 4, 6, 9, 12, 18, and 36.
5. ( 2 4 6 12 18 )
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
36
5136 is divisible by 2, 3 and 4. It is not divisible by 5, 9 and 10. The tests: 5136 ends in 6 which is divisible by 2, so 5136 is divisible by 2 (5136 = 2 x 2568) (This can also be stated that as 5136 is even (since it ends in 6), 5136 is divisible by 2.) 5 + 1 + 3 + 6 = 15 which is divisible by 3, so 5136 is divisible by 3 (5136 = 3 x 1712) 5136 ends with 36 which is divisible by 4, so 5136 is divisible by 4 (5136 = 4 x 1284) 5136 ends in 6 which is neither 5 nor 0 so it is not divisible by 5 5 + 1 + 3 + 6 = 15 which is not divisible by 9 so 5136 is not divisible by 9 5136 ends in 6 which is not 0 so 5136 is not divisible by 10
60 is divisible by 3, 4, 5, and 6.
25 over 36
20
numbers that are divisible of 5 and 6 is basically adding the same number repeating itself. for example, 5 times 4 is the same as 5+5+5+5. five added four times. 5 is divisible of 5 10 15 20 25 30 35 40 45 and so on. 6 is divisible to 6 12 18 24 30 36 42 48 54 and so on.
Yes 36/6 = 6
650130 is not divisible by 4, but it is divisible by 2, 3, 5, 6, and 10
No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).