36
4- If the last two digits are divisible by 4, the whole number is divisible by 4. 6- If the number is even and also divisible by 3, it is divisible by 6.
18
60 is divisible by 3, 4, 5, and 6.
the least number divisible by 1, 2, 3, 4 & 6 is 12.
To determine if a number is divisible by 6, we need to check if it is divisible by both 2 and 3. The number 34614 is divisible by 2 because it is even (the last digit is even). To check if it is divisible by 3, we sum the digits: 3 + 4 + 6 + 1 + 4 = 18, which is divisible by 3, so 34614 is divisible by 3. Therefore, 34614 is divisible by 6. To check if it is divisible by 9, we sum the digits again: 3 + 4 + 6 + 1 + 4 = 18, which is divisible by 9, so 34614 is divisible by 9 as well.
Any number (however many digits) that is divisible by 3 and by 4 MUST be divisible by 6. So there cannot be a number that meets the requirements of the question.
18
To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
The number 44 is divisible by: 2 - 44/2 = 22 4 - 44/4 = 11 The number is not divisible by 3, 5, 6, or 10.
Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.This is because the prime factor of 3 is [3] -- in other words, 3 is a prime number -- and the prime factors of 4 are [2, 2].Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.