3805 is divisible by 5 evenly whereas 3805 is not divisible by 8 evenly
235,910 is divisible by: 1 2 5 10 31 62 155 310 761 1522 3805 7610 23591 47182 117955 235910.
760 is evenly divisible by both 5 and 8
3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
42 is divisible by 14, but not divisible by 8, 5 nor 9.
280/5 = 56 280/8 = 35 Therefore, 280 is divisible by both 5 and 8.
if Divisible by 5 = ends in 0 or 5 if Palindrome = spelled the same forwards as backwards then number begins and ends with either 0 or 5 5_5, or 0_0 Sum is divisible by 8 5+5=10 16=divisible by 8 565
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
5, no. 8, yes.
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
No, it does not go in evenly. To be divisible by 8 it would need to be divisible by two and 5 being and odd number is not.
840 is the smallest number that is divisible by 5 6 7 and 8.
Yes. The answer is 5.
No. 35 is divisible by: 1, 5, 7, 35.
3795 ÷ 5 = 759 3795 ÷ 8 = 474.375
5+2+1=8 and 8 is not divisible by 3.
Yes, 8 is divisible by any number but, of your list, the only numbers by which 8 is EVENLY divisible are 1, 2, 4, and 8.
Out of that list, 40 is divisible by 2, 4, 5, 8 and 10.
1, 2, 4, 5, 7, 8
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
There are many numbers that are evenly divisible by 5 and 8. The lowest number is 40. For a number to be evenly divisible by 5, it has to end in a 5 or a 0. One method to use is to multiply 8 by different numbers and if the product ends in a 5 or 0, then it is also evenly divisible by 5. Another method is to keep adding 40 to the first answer of 40, so that 80, 120, 160, 200, etc. are all evenly divisible by 5 and 8.
Not equally.116 ÷ 8 = 14 remainder 5
Any number ending in 5 or 0 is divisible by 5, just like any number ending in 2, 4, 6, 8 or 0 is divisible by 2.
There is no 5 digit number which is divisible by 23456910 (an 8-digit number)..
352 is divisible by 1, 2, 4 and 8; not by 3, 5, 6 and 9
182340 is divisible by all but 8 out of that list.