No.
All multiples of 8 are even (end in 2, 4, 6, 8 or 0) but 382169 is odd (ends in 1, 3, 5, 7 or 9) so it cannot be a multiple of 8 and thus cannot be divisible by 8.
To test for any [even] number being divisible by 8 add the units digit to twice the tens digit to four times the hundreds digit; if this sum is divisible by 8, then so is the original number. If the test is repeated until a single digit remains, only if this digit is 8 is the original number divisible by 8, otherwise if it is 1-7 it gives the remainder when the original number is divided by 8 (if it is 9, the remainder is 1).
For 382169 this gives 9 + 2x6 + 4x1 = 9 + 12 + 4 = 25. 25 is not divisible by 8, so 382169 is not divisible by 8.
Using the test on 25 gives 5 + 2x2 + 4x0 = 9, again not divisible by 8 (remainder is 1).
8 is NOT a prime number. It is divisible by 2, for example.
No. It is even and so divisible by 2.
If the last 3 digits are divisible by 8, the number is divisible by 8.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
Any number is divisible by its factors.
No. To find whether the number is divisible by 3, you add each digits and if it's equal to 9 then it's divisible by 3 because 9 is divisible by 3. 9 + 8 + 2 = 19, 1 + 9 = 10... so it's not divisible by 3.
Neither is divisible by 8.
152 is divisible by 8, and the answer is 19.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
No
4 is divisible by 1, 2 and 4. So is 8. If a number is divisible by 8, it will also be divisible by 4.
Yes. 8 / 4 = 2 8 is also divisible by 2 and 8.