No, it's not.
1, 3, 9, 383, 1149, 3447.
383 is a prime number. It is only evenly divisible by itself and one.
To determine if 90005 is divisible by a specific number, we need to check if the number divides evenly into 90005 without leaving a remainder. For example, to check if 90005 is divisible by 5, we would divide 90005 by 5. If the result is a whole number without a remainder, then 90005 is divisible by 5. Similarly, this process can be applied to other numbers such as 2, 3, 4, 6, 9, 10, and so on.
90005=5*47*383 Hence, 5 is the only divisor of 90005 among those listed.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
A number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
NO. 313 is not divisible by 3.A number is divisible by 3 if the sum of the digits is divisible by 3.313 = 3 + 1 + 3 = 7Note: 7 not divisible by 3 thus, 313 is not divisible by 3.
3 is not divisible by 126. 126 is divisible by 3.
1x6,743 not divisible by 2 no its not divisible by 3????