No, 39 isn't prime.
Since 39 is a factor of 78, it is automatically the GCF.
Since 39 is a factor of 78, it is automatically the GCF.
78 6 x 13 (2x3) x 13 The numbers 2, 3, and 13 are prime numbers, so the factor tree is complete. An alternate version of a factor tree for 78 is: 78 2 x 39 2 x (3x13)
The GCF is: 39
78 = 13 x 3 x 2 Therefore, the greatest prime factor of 78 is 13.
To find the least common multiple (LCM) of 26, 13, and 39, we first need to factorize each number into its prime factors. 26 = 2 x 13 13 = 13 39 = 3 x 13 Then, we identify the highest power of each prime factor that appears in any of the factorizations. In this case, the LCM is 2 x 3 x 13 = 78. Therefore, the least common multiple of 26, 13, and 39 is 78.
The greatest common factor is 5 * * * * * Actually, it is 39
Not.
GCF(39, 78, 26) = 13.
The GCF of 78 and 117 is 39Factors of 78: 1 2 3 6 13 26 39 78Factors of 117: 1 3 9 13 39 117The GCF of 78 and 117 is: 39The GCF is 39.The GCF is 39.
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
No, 13 and 39 are not relatively prime. 13 is a factor of 39.