39 divided by 10 is 3.9 so 39 goes into 10 3times
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
390 is divisible by 3: 390/3 = 130 390 is not divisible by 9: 390/9 = 43.3 recurring (that is, 43.3333..) 390 is divisible by 10: 390/10 = 39
Yes.
No, it is divisible by 1, 3, 13, 39.
The GCF is: 3The GCF of 39 and 30 is 3. There are no further divisible numbers in common. This leaves you with 13 and 10 respectively.
40 is nearest to 39 and is exactly by divisible 4
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
No - 39/4 = 9.75
No.
To show that the product of 56 and 39 is exactly divisible by 21, you can check if both numbers are divisible by the prime factors of 21, which are 3 and 7. Since 56 is divisible by 7 (56 ÷ 7 = 8) and 39 is divisible by 3 (39 ÷ 3 = 13), their product will also be divisible by both 3 and 7. Therefore, 56 x 39 is divisible by 21.
Yes; if 39 is divided by 3, you get 13. Another way to check this is add 13+ 13+ 13, and you will get 39.
All multiples of 39, which is an infinite number.