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Q: Is 42 divisible by 2 3 4 5 6 9 or10?

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42 is divisible by 2, 3 and 6 but not by 9.

42 is divisible by: 1 2 3 6 7 14 21 and 42.

42 is divisible by 2 and 6.

Its digits add up to a multiple of 3.

it is divisible by all three

42 is divisible by 2, 3, 6, & 7

Yes, 3 x 14 = 42. It is also divisible by these numbers: 1 2 3 6 7 21 and 42.

Out of that list, 2, 3 and 6

Yes. 126 divided by 3 is 42 42 is also divisible by 3. 42 ÷3 = 14 The prime factors of 126 are 2, 3, 3, and 7.

The smallest number that can be divisible by these three numbers is 42. If 42 is multiplied by 2, 3, 7, or any number divisible by only one of those numbers then that number as well will be divisible by 2, 3, and 7.

2 or 8

No , the answer would be 42 and 2/3

Yes. (all of them)

1, 2, 3, 6, 7, 14, 21 and 42.

LCM(2, 3, 7) = 42

1, 2, 3, 6, 7, 14, 21, 42.

1, 2, 3 and 6.

No. Its prime factors are 7 and 3; the sole prime factor of 8 is 2, therefore 42 cannot be divisible by 8.

1, 2, 3, 6, 7, 14, 21, 42.

2, 3, 6, 7, 14 and 21

42 is a composite number as it is divisible by 1, 2, 3, 6, 7, 14, 21 and 42.

Yup!

126 is divisible by 2, 3 and 9 but not the other 2 126/2= 63 126/3= 42 126/9= 14

42, 48, 54, and 60 is. -- If it's 'even' then it must also be divisible by 2 . -- If it's divisible by 3 and also by 2, then it must be divisible by 6 . -- The multiples of 6 between 40 and 60 are 42, 48, 54, and 60 .

It is divisible by any of its factors which are: 1, 2, 3, 6, 7, 14, 21 and 42