Q: Is 430 divisible by 2 and 5?

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If you want your answer to be a whole number, it is divisible by 2 and 5.

yes To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8}; The last digit of 430 is 0, which is one of these so it is divisible by 2.

There is an infinite number of numbers that are divisible by 430.

hcf(520, 430) = 10 520 = 23 x 5 x 13 430 = 2 x 5 x 43 hcf = 2 x 5 = 10

because 10 is also divisible by 2 and 5.

Related questions

If you want your answer to be a whole number, it is divisible by 2 and 5.

Yes.

2, 5, 6, and 10.

yes To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8}; The last digit of 430 is 0, which is one of these so it is divisible by 2.

Ok look, it is divisible by 2, 5, and 10. :-)

First determine which of the numbers are divisible by 5.They are:70430525Then you find the sum of these. 70+430=500. 500+525=1025.

The factors of 430 are 2, 5, and 43 or 2 times 5 time 43 is 430.

No. 430 is not evenly divisible by three.

There is an infinite number of numbers that are divisible by 430.

430 = 2 * 5 * 43

Find the sum of the first hundred even natural number divisible by 5?

-- Neither 2 nor 5 is divisible by 18. -- 18 is divisible by 2, but not by 5.