yes
To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};
The last digit of 430 is 0, which is one of these so it is divisible by 2.
Yes
If you want your answer to be a whole number, it is divisible by 2 and 5.
There is an infinite number of numbers that are divisible by 430.
To find the sum of the numbers 70, 164, 430, and 525 that are divisible by 5, we first identify which numbers meet this criterion. The numbers 70, 430, and 525 are divisible by 5. Their sum is 70 + 430 + 525 = 1025. The number 164 is not included since it is not divisible by 5.
No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.
Yes
If you want your answer to be a whole number, it is divisible by 2 and 5.
Yes.
2, 5, 6, and 10.
No. 430 is not evenly divisible by three.
There is an infinite number of numbers that are divisible by 430.
To find the sum of the numbers 70, 164, 430, and 525 that are divisible by 5, we first identify which numbers meet this criterion. The numbers 70, 430, and 525 are divisible by 5. Their sum is 70 + 430 + 525 = 1025. The number 164 is not included since it is not divisible by 5.
Ok look, it is divisible by 2, 5, and 10. :-)
Olympic years are divisible by 4. No games scheduled for 430 BCE.
86. Along with 172, 258, 344, 430, ...
First determine which of the numbers are divisible by 5.They are:70430525Then you find the sum of these. 70+430=500. 500+525=1025.
430