Yes but it will have a remainder of 1
To determine if 441 is divisible by 3, you can add the digits of 441 together: 4 + 4 + 1 = 9. Since 9 is divisible by 3, then 441 is also divisible by 3. This is because a number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, 441 is divisible by 9. To determine if a number is divisible by 9, you can add up its digits. In this case, 4 + 4 + 1 = 9, which is divisible by 9. Therefore, 441 is divisible by 9.
The multiples of 441 (which are infinite) are all divisible by 441, including these: 441, 882, 1323, 1764, 2205, 2646, 3087, 3528, 3969 . . .
Yes but it will have a remainder because 5 is not a factor of 441
1, 3, 7, 9, 21, 49, 63, 147, 441
All multiples of 147 are divisible by 147: 147, 294, 441, 588, 735, ...
441 divided by 2 is 220.5
441 / 2 is equal to 220.5
Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.
Dividing the numerator and denominator of the fraction by 21, 42/441 is equal to 2/21.
√441 = √(3^2 × 7^2) = 3 × 7.
The factors of 441 are the numbers that can be multiplied together to give 441. They include 1, 3, 7, 9, 21, 49, 63, and 147, as well as 441 itself. Additionally, 441 can be expressed as (21^2) or (3^2 \times 7^2), indicating that its prime factors are 3 and 7.