Yes but it will have a remainder of 1
The multiples of 441 (which are infinite) are all divisible by 441, including these: 441, 882, 1323, 1764, 2205, 2646, 3087, 3528, 3969 . . .
no
Yes, 3 × 147 = 441
Yes but it will have a remainder because 5 is not a factor of 441
1, 3, 7, 9, 21, 49, 63, 147, 441
All multiples of 147 are divisible by 147: 147, 294, 441, 588, 735, ...
441 divided by 2 is 220.5
441 / 2 is equal to 220.5
Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.
Dividing the numerator and denominator of the fraction by 21, 42/441 is equal to 2/21.
√441 = √(3^2 × 7^2) = 3 × 7.
2 + 3 + 5 + 431 = 441