All multiples of 147 are divisible by 147: 147, 294, 441, 588, 735, ...
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
Whole numbers, composite numbers, odd numbers, numbers divisible by 3, and many more.
1, 3, 49, and 147
All numbers are divisible by 1.
Both of these numbers are divisible by 3 and 7. The factors of 105 is 21 x 5 and that of 147 is 21 x 7. So the LCM is 21 x 35 = 735.
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
No, they're both divisible by three
Whole numbers, composite numbers, odd numbers, numbers divisible by 3, and many more.
Two numbers: 126 and 147
1, 3, 49, and 147
1, 3, 49, and 147
No, 3 is a factor of both. Note that the digits of 120 add up to 3 and those of 147 add up to 12. Both are multiples of 3 so the numbers 120 s and 147 are divisible by 3 and not relatively prime
-4
All numbers are divisible by 1.
Both of these numbers are divisible by 3 and 7. The factors of 105 is 21 x 5 and that of 147 is 21 x 7. So the LCM is 21 x 35 = 735.
Yes. 1,323 / 9 = 147
It i.s easy to see that 147 is composite. Simply add up the digits. 1 + 4 + 7 = 12. 12 is divisible by three, therefore 147 is divisible by three ! This trick also works for division by nine.