All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
Whole numbers, composite numbers, odd numbers, numbers divisible by 3, and many more.
1, 3, 49, and 147
All numbers are divisible by 1.
Both of these numbers are divisible by 3 and 7. The factors of 105 is 21 x 5 and that of 147 is 21 x 7. So the LCM is 21 x 35 = 735.
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
Whole numbers, composite numbers, odd numbers, numbers divisible by 3, and many more.
No, they're both divisible by three
Two numbers: 126 and 147
1, 3, 49, and 147
1, 3, 49, and 147
No, 3 is a factor of both. Note that the digits of 120 add up to 3 and those of 147 add up to 12. Both are multiples of 3 so the numbers 120 s and 147 are divisible by 3 and not relatively prime
To determine if 441 is divisible by 3, you can add the digits of 441 together: 4 + 4 + 1 = 9. Since 9 is divisible by 3, then 441 is also divisible by 3. This is because a number is divisible by 3 if the sum of its digits is divisible by 3.
-4
All numbers are divisible by 1.
Both of these numbers are divisible by 3 and 7. The factors of 105 is 21 x 5 and that of 147 is 21 x 7. So the LCM is 21 x 35 = 735.
Yes. 1,323 / 9 = 147