45 is divisible by 5 and 9 (not 10) because 45 is a multiple of 5 and 9 (not 10).
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
Only 5 is the factor of 45 because 45 is divisible by 5. But 12 is not a factor of 45 because 45 is not divisible by 12.
45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.
The number that is between 40 and 50 and is divisible by both 3 and 5 is 45. To determine if a number is divisible by both 3 and 5, you must ensure it is divisible by both 3 and 5 without leaving a remainder. In this case, 45 meets this criteria as it is divisible by both 3 (45 ÷ 3 = 15) and 5 (45 ÷ 5 = 9).
9/10 is in its simplest form. 910/45 = 182/9
Yes.
no yes 9 goes into 45 5 times
All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.
It is: 45
45 is divisible by 1, 3, 5, 9, 15, and 45.
Neither of them are prime. 45 is divisible by 5 and 9. 1024 is divisible by 2 and 512.
45 is divisible by 1, 3, 5, 9, 15, 45.