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Clearly, both 810 and 910 are divisible by 5.
A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3.
In your example, 810 components add up to 9, which is divisible by 3.
But the components of 910 add up to 10 which is not so divisible.
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What is a counter example to falsify If x is an integer divisible by 3 then x2 is an integer divisible by 3?
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
Is 12345 divisible by 3?
12345 is divisible by 3 and the answer is 4115
Why is 138 divisible by 3?
Well, to find out if any number is divisible by 3, you add up the number's factors. If the number you come up with is divisible by 3, then the entire number is divisible by 3.For example:138= 1+3+8= 1212 is divisible by 3.
How can you tell that 42 is divisible by 3?
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
Is 166 divisible by 3?
It is not evenly divisible.
