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Clearly, both 810 and 910 are divisible by 5.

A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3.

In your example, 810 components add up to 9, which is divisible by 3.

But the components of 910 add up to 10 which is not so divisible.

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Q: What is equally divisible by 3 and 5 810 or 910?

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48 is divisible by: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.

12345 is divisible by 3 and the answer is 4115

Well, to find out if any number is divisible by 3, you add up the number's factors. If the number you come up with is divisible by 3, then the entire number is divisible by 3.For example:138= 1+3+8= 1212 is divisible by 3.

It is not evenly divisible.

Related questions

810 is divisible by 3. No need to do anything to it.

Yes.

810/2 = 405 810/3 = 270 * 810/4 = 202.5 810/5 = 162 810/6 = 135 810/9 = 90 810/10 = 81 so 810 is divisible by 2 3 5 6 9 10 but not by 4

No, but I suspect you want to know if 810 is divisible by those numbers. Out of that group, 810 is divisible by 2, 3, 5, 6, 9 and 10

780 equally divisible by both 3 and 5. 320 by 5 not by 3

Yes. 810 is divisible by these numbers: 1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 81, 90, 135, 162, 270, 405, 810.

no

No, its not able to divide equally

Yes. answer is 236

No

No because it will have a remainder

No - 614/3 = 204.6 recurring (that is, 204.6666...)