No, it is composite.
492 = 2 x 2 x 3 x 41
They are: 2, 2, 3 and 41
Yes, 6 is a factor of 492. If you divide 492 by 6 you get 82 with no remainder. The fact that there was no remainder means that the first number is a factor of the second number. Taking this to the obvious conclusion; the prime factors of 492 are 2, 2, 3, and 41. 6 is 2 times 3, so it is a non prime factor, but it is a factor nontheless.
As an even number greater than 2, 492 is divisible by 2 and therefore composite. Its positive integer factors are: 1, 2, 3, 4, 6, 12, 41, 82, 123, 164, 246, 492
28% of 492= 28% * 492= 0.28 * 492= 137.76
1, 2, 3, 4, 6, 12, 41, 82, 123, 164, 246, 4922, 3 and 41 are prime.
71 + 73 + 79 + 83 + 89 + 97 = 492
2 x 2 x 3 x 41
ANSWER: 49200%492= 492 * 100%= 49200%
492-485 = 7
1-492 = -491
18 + 492 = 510