no
numbers divisible by 5 end with either a 5 or a 0
No - 25 is only divisible by 5 and 49 is not divisible by 5 so the fraction cannot be simplified.
Yes, 245 / 5 = 49
Both 49 and 100 are divisible by 1 and themselves. In addition, 49 is divisible by 7 (7 x 7 = 49), and 100 is divisible by 2 and 5 (2 x 50 = 100, 5 x 20 = 100). So, the numbers that will divide into both 49 and 100 are 1 and the numbers 7, 2, and 5.
1, 5, 7, 35, 49, 245
No. 49 is only divisible by 1, 7 and 49.
Besides 49 & 98? The numbers divisible by 49 are infinite.
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
The number is 40.
1, 5, 7, 35, 49, 245
LCM of a prime number and a composite number is equal to their product if the latter is not divisible by the former. 5 is a prime number and 49 is a composite number. 49 is not divisible by 5. So, LCM(5,49) = 5 x 49 = 245. Actually the reason behind this is that both(5 and 49) do not share any common factors except 1, so the LCM is equal to the product.
49 is divisible by 1, 7 and 49
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490