The reason is that 49 is divisible with numbers other than 1 and itself. 49 is divisible by 1, 7 and 49.
There are no such numbers. The only number in the range that is divisible by 35 is 70 and that is not divisible by 9.
all of them but 49, which is divisible by 7
Both 49 and 100 are divisible by 1 and themselves. In addition, 49 is divisible by 7 (7 x 7 = 49), and 100 is divisible by 2 and 5 (2 x 50 = 100, 5 x 20 = 100). So, the numbers that will divide into both 49 and 100 are 1 and the numbers 7, 2, and 5.
1, 2, 7, 14, 49, 98.
Besides 49 & 98? The numbers divisible by 49 are infinite.
Any of its multiples
The reason is that 49 is divisible with numbers other than 1 and itself. 49 is divisible by 1, 7 and 49.
343 is divisible by 1, 7, 49, 343.
There are no such numbers. The only number in the range that is divisible by 35 is 70 and that is not divisible by 9.
no numbers divisible by 5 end with either a 5 or a 0
all of them but 49, which is divisible by 7
There are 49 numbers between 1 and 100 that are divisible by two.
Both 49 and 100 are divisible by 1 and themselves. In addition, 49 is divisible by 7 (7 x 7 = 49), and 100 is divisible by 2 and 5 (2 x 50 = 100, 5 x 20 = 100). So, the numbers that will divide into both 49 and 100 are 1 and the numbers 7, 2, and 5.
A number being divisible by another number is a different way of saying the factors of a number. Factors are numbers you can multiply together to get another number. 49: 1, 7, 49
5,19, 29, 61, 41, 127 10 is divisible by 2 so not prime 49 is divisible by 7 57 is divisible by 3
1, 2, 7, 14, 49, 98.