Loading...

500 numbers are divisible by 2.

There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.

500 numbers in the range [1, 1000] are divisible by 2.

No. 500 is not evenly divisible by nine.

Exclusively, meaning not including 200 and 500, there are 149 even (divisible by two) numbers between 200 and 500.

500 is not a prime number. Other than 2, if a number is even, it is not prime since it is divisible by 2.

453

Yes. As both the numerator (2) and the denominator (500) are divisible by the same number (2), the fraction can be simplified to 1/250

510,540,570,

How about 450

.728 = 728/1000 (the last digit is in the Thousands place so it is the whole number over one thousand) They are both divisible by 2 so: 728 / 2 = 364 and 1000 / 2 = 500 728/1000 = 364/500 That is also divisible by 2 so: 364 / 2 = 182 and 500 / 2 = 250 That is also divisible by 2 so: 182 / 2 = 91 and 250 / 2 = 125 728/1000 = 364/500 = 182/250 = 91/125 91/125 is fully simplified and is your answer.

1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250, 500

To find out if a number is divisible by 3 add up all it's digest and check if the total is divisible by 3. to check if a number is divisible by 2 check if the last digit is divisible by 2. So one such number is 405.

Just 1.

No.

Eight of them.

Try 300

405 is one example.

432, 468

There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?

There are 63 numbers 1 to 500 that are divisible by six but not by eight.

There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.

There are 500 such numbers. How about 1818 as an example?

To get a number like this, it CANNOT be even. The number 453 is divisible by 3(goes into 453 ninenty one times), but not by 2.

Yes. 500 is evenly divisible by four.