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Q: Is 54 divisible by 2 3 9?

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54 is divisible by: 1 2 3 6 9 18 27 54.

A number is divisible by 6 if it is divisible by 2 and 3. 54/6 = 9, 54/3 = 18, 54/2 = 27 - therefore, 54 is divisible by 6.

54 is divisible by 1, 2, 3, 6, 9, 18, 27, 54 Multiples of 54 are divisible by 54.

No. However 54 is divisible by 3 since 54 = 3 times 18. Also, the sum of the digits of 54 is 9 and 9 = 3 times 3. (if the sum of the digits is divisible by 3, so is the number and conversely.)

No. 54 is only evenly divisible by these numbers: 1, 2, 3, 6, 9, 18, 27, 54.

Also, remember, that if a number is divisible by 9, then it is automatically divisible by three.

54

The positive whole-number "factors" of 54 are: 1, 2, 3, 6, 9, 18, 27, and 54.

Yes, 18 times 3 = 54. There is a very easy way to tell if a number is divisible by 3. Add up the digits in the number. If the sum of the digits is divisible by 3, then the number is divisible by 3. For example, 5 + 4 = 9, and 9 is obviously divisible by 3. So, 54 is too.

Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.

27 for one then there's 36, 45, 54, 18 in short, any number divisible by 9 is also divisible by 3

The numbers 2, 3, and 9 are all divisible by 1.

no because to be divisible by 9 the number has to equal 9 for instance 2+9+3+8=22 so it is not divisible by 9. But 32121 3+2+1+2+1=9 so it is divisible by 9

42 is divisible by 2, 3 and 6 but not by 9.

2, 3 and 6. There is also 1 and 9.

All are divisible by 9. (and by 3) 54 = 6 x 9 36 = 4 x 9 81 = 9 x 9

1262 is even, so 1262 is divisible by 2. 1 + 2 + 6 + 2 = 11 which is not divisible by 3 nor 9, so 1262 is not divisible by 3 nor 9.

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

It is divisible by 2, 5 and 10, but not 3 and 9.

It is evenly divisible by 2 and 10 but not by 3 and 9.

No.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10

No, because when something is divisible by 6, it is divisible by 2 or 3. This is divisible by 3, but not 2.

29,178 is divisible by 2, 3 and 9, not by 5 or 10.