Using the tests for divisibility:
2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3
234 is even so 234 is divisible by 2.
234 is divisible by both 2 & 3 so 234 is divisible by 6
2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9
Thus 234 is divisible by all 3, 6 & 9.
The factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234
1350 is divisible by all of the numbers of 3, 6 and 9
The smallest number divisible by 3 6 and 9 is 18.
yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.
468 is divisible by all of its factors, 1, 2, 3, 4, 6, 9, 12, 13, 18, 26, 36, 39, 52, 78, 117, 156, 234, and 468.
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
The factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
Yes, 234 it is divisible by 9 to give an answer that is a whole number.9 x 30 = 270 = too high9 x 20 = 180 = OKso234 - 180 = 54 which is divisible by 9so9 x 6 = 54so20+6 = 26(and the answer for 234/9 = 26).
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6
72,344 is not evenly divisible by 3 or by 6 or by 9.
Yes, 234 is divisible by 9 because on dividing 234 by 9 we get 26 as quotient and 0 as remainder. A number is divisible by another number if: 1- Quotient is a whole number 2- Remainder is zero
234 ========== or 243
1350 is divisible by all of the numbers of 3, 6 and 9
42 is divisible by 2, 3 and 6 but not by 9.