Yes. The result is 187.
No. Since the sum of its digits is divisible by 3, (5 + 6 + 1 = 12), the whole thing is divisible by 3. (neat little trick) Since it has at least one factor besides '1' and itself, it's not a prime number.
The prime factorization of 561 is: 3 x 11 x 17
It is 561
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
No. Since the sum of its digits is divisible by 3, (5 + 6 + 1 = 12), the whole thing is divisible by 3. (neat little trick) Since it has at least one factor besides '1' and itself, it's not a prime number.
If a numbers digits add up to a number that is divisible by nine, the number is divisible by nine. Example~ 486 4+8+6=18 Since 18 is divisible by 9, 486 is divisible by 9. 561 5+6+1=12. 561 isn't divisible by 9.
0.0053
For a number to be divisible by 3, its digit sum has to be divisible by 3. For a number not to be divisible by 2, the last digit must be a 1,3,5,7 or 9. Using these rules, the numbers between 500 and 600 that divide by 3 but not 2 become clear: 501, 507, 513, 519, 525, 531, 537, 543, 549, 555, 561, 567, 573, 579, 585, 591 and 597
The factors of 561 are 1, 3, 11, 17, 33, 51, 187, and 561.
0.0553
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
1 3 11 17 33 51 187 561.
187 is divisible by 17 and 11. 187 divided by 17=11.
The factors are 1, 3, 11, 17, 33, 51, 187 and 561
The prime factorization of 561 is: 3 x 11 x 17
The greatest common factor of 561 , 54168 = 3