Yes. The result is 187.
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No. Since the sum of its digits is divisible by 3, (5 + 6 + 1 = 12), the whole thing is divisible by 3. (neat little trick) Since it has at least one factor besides '1' and itself, it's not a prime number.
The prime factorization of 561 is: 3 x 11 x 17
It is 561
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.