No. Since the sum of its digits is divisible by 3, (5 + 6 + 1 = 12), the whole thing is divisible by 3. (neat little trick) Since it has at least one factor besides '1' and itself, it's not a prime number.
The prime factorization of 561 is: 3 x 11 x 17
It is 561
561 x 561 = 5612 = 314,721
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
No. Since the sum of its digits is divisible by 3, (5 + 6 + 1 = 12), the whole thing is divisible by 3. (neat little trick) Since it has at least one factor besides '1' and itself, it's not a prime number.
If a numbers digits add up to a number that is divisible by nine, the number is divisible by nine. Example~ 486 4+8+6=18 Since 18 is divisible by 9, 486 is divisible by 9. 561 5+6+1=12. 561 isn't divisible by 9.
0.0053
The factors of 561 are 1, 3, 11, 17, 33, 51, 187, and 561.
0.0553
For a number to be divisible by 3, its digit sum has to be divisible by 3. For a number not to be divisible by 2, the last digit must be a 1,3,5,7 or 9. Using these rules, the numbers between 500 and 600 that divide by 3 but not 2 become clear: 501, 507, 513, 519, 525, 531, 537, 543, 549, 555, 561, 567, 573, 579, 585, 591 and 597
1 3 11 17 33 51 187 561.
187 is divisible by 17 and 11. 187 divided by 17=11.
The greatest common factor of 561 , 54168 = 3
The factors are 1, 3, 11, 17, 33, 51, 187 and 561
The prime factorization of 561 is: 3 x 11 x 17
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.