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Is 58 b a c

Updated: 9/27/2023
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A triangle has a perimeter of 58 cm the longest side is twice as long as the shortest side the third side is 10cm longer than the shortest side what are the lengthes of the three sides?

In order of length a + b + c = 58; a = 2c, b = c + 10; Substitute: 2c + (c + 10) + c = 58 Gather: 4c + 10 = 58 c = 48/4 = 12 Sides are therefore 24 cm, 22 cm and 12 cm.


How do you divide by 5 and have a remainder with 3 and 8 and a remainder of 2 and 9 and a remainder of 4?

The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.


What is c-3 equals 58?

c=61 - 3 =58


Ms. Peters said that 5 8 of her dance students prefer ballet Which percent is equal to 5 8 A 58 B 62.5 C 580 D 625?

B: 62.5%


Maria keeps her four stuffed bears lined up on a shelf over her bed how many arrangements of the bears are possible?

The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a

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A triangle has a perimeter of 58 cm the longest side is twice as long as the shortest side the third side is 10cm longer than the shortest side what are the lengthes of the three sides?

In order of length a + b + c = 58; a = 2c, b = c + 10; Substitute: 2c + (c + 10) + c = 58 Gather: 4c + 10 = 58 c = 48/4 = 12 Sides are therefore 24 cm, 22 cm and 12 cm.


How do you divide by 5 and have a remainder with 3 and 8 and a remainder of 2 and 9 and a remainder of 4?

The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.The smallest positive integer, p, that satisifesp = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.So the solution set is 58 + 360k where k is an integer.


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What is c-3 equals 58?

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