answersLogoWhite

0


Best Answer

The smallest positive integer, p, that satisifes

p = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.

So the solution set is 58 + 360k where k is an integer.

The smallest positive integer, p, that satisifes

p = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.

So the solution set is 58 + 360k where k is an integer.

The smallest positive integer, p, that satisifes

p = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.

So the solution set is 58 + 360k where k is an integer.

The smallest positive integer, p, that satisifes

p = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.

So the solution set is 58 + 360k where k is an integer.

User Avatar

Wiki User

11y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

11y ago

The smallest positive integer, p, that satisifes

p = 5a + 3 = 8b + 2 = 9c + 4 (where a, b and c are integers) is 58.

So the solution set is 58 + 360k where k is an integer.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you divide by 5 and have a remainder with 3 and 8 and a remainder of 2 and 9 and a remainder of 4?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

When you divide by 5 the remainder is 4?

When you divide by 5, the remainder can be 0, 1, 2, 3, or 4, but no more than 4.


What is the largest remainder one can have when divide by 5?

5 */. 3= 1 Remainder:2


What is 14 divided by 3 remainder?

4.6667


What is the remainder when 28 is divided by 6?

4.6667


Find the smallest number that meets all of these conditions divide the number by 5 remainder 3 divide the number by 8 remainder 2 divide the number by 9 remainder 4?

58


How do you write a remainder as a decimal?

you take your remainder and divide it by your divisor 9 divided by 4 = 2, remainder 1 the divisor is 4, so 1/4 = .25 therefore 2 + .25 = 2.25


Can you get a remainder when you divide by nine?

Yes - the remainder can be either 1, 2, 3, 4, 5, 6, 7, or 8.


If you divide a whole number by three what is the largest possible for the remainder?

If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.


When you divide by 4 what remainders are possible?

20 / 4 = 5 (no remainder) 21 / 4 = 5 remainder 1 22 / 4 = 5 remainder 2 23 / 4 = 5 remainder 3 24 / 4 = 6 (no remainder) Therefore the numbers that can remain after you've divided a number by four are 0, 1, 2, and 3.


The number you are thinking of is between 12 and 32 when you divide it by 5 it leaves a remainder of 1 when i divide it by 4 it leaves a remainder of2?

26. This is because when you divide 26 by 5, you have a remainder of 1, and when you divide it by 4, you have a remainder of 2


How do you change a fraction to a mixed fraction?

You divide by the denominator. You write the result of the division as the whole number, and the remainder on top of the old denominator. Example: 14/3; divide 14 by 3. The result is 4, remainder is 2, so you write the result as 4 2/3.


What is 95 divide by 4 and there a remainder?

23.75