No.
Closure under multiplication is a property of a set of numbers. It requires that if x and y are elements of the set (not necessarily different), then x*y is also an element of the set.
If the set consists only of the number 5, ie S = {5}. Since 5 belongs to S, closure would require that 5*5 belongs to the set. It clearly does not and so the set cannot be closed.
By definition, a product of two primes has atwo factors (other than 1 and itself) and so it cannot be prime. So the set is not closed.
No.
No. A number cannot be closed under addition: only a set can be closed. The set of rational numbers is closed under addition.
The set of even numbers is closed under addition, the set of odd numbers is not.
Let + (addition) be a binary operation on the set of odd numbers S. The set S is closed under + if for all a, b ϵ S, we also have a + b ϵ S. Let 3, 5 ϵ the set of odd numbers 3 + 5 = 8 (8 is not an odd number) Since 3 + 5 = 8 is not an element of the set of the odd numbers, the set of the odd numbers is not closed under addition.
Quite simply, they are closed under addition. No "when".
no, not all prime numbers are closed under addition. why? because, when you add 2 prime numbers you will not always get a prime number. example: 5+3= 8 5 and 3 are prime numbers but their sum is 8 which is a composite number..
It means whatever members of the set you subtract, the answer will still be a member of the set. For example, the set of positive integers is not closed under subtraction, since 3 - 8 = -5
The numbers are not closed under addition because whole numbers, even integers, and natural numbers are closed.
-2 - (-5) = -2 + +5 = +3. (+3 is not in the set of negative numbers.)
Yes they are closed under multiplication, addition, and subtraction.
Yes, decidable languages are closed under concatenation.