Q: Is 6.2 prime composite or n either?

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Prime if n=1, composite otherwise.

Composite. It is divisible by 3 for any n.

Are you asking is 525 prime? The a nswer is no. It is a composite number. Are you aski ng what is the prime factorizatio n of 525? Prime factorizatio n of 525 = 3 * 5 * 5 * 7

No, if you think that you have it, you can always find one that is larger. Take, for example you find an even composite number (all even numbers, except 2 - which is the only even prime, are composite). Call this number N. Now add 2 to N for N+2, which is also even, so it is also a composite. What about odd composites: if you find an odd composite(M), then add 1 to it: odd+odd=even, so M+1 is even, which is also composite. You can keep going forever.

One way is to divide by all smaller numbers, up to the square root of that number. In practice, you can omit even numbers (except 2), and any number which you know is prime. Thus, for any number up to 120, it is enough to try to divide by 2, 3, 5, 7. If any of these divisions yields an integer, then the number you divided by is a factor - and your original number is composite.

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Prime if n=1, composite otherwise.

2 is a prime number. 2 times anything but 1 is composite.

It is one

A composite number is a positive integer which has a positive divisor other than one or itself. In other words, if 0 < n is an integer and there are integers 1 < a, b < n such that n = a × b then n is composite. By definition, every integer greater than one is either a prime number or a composite number. The number one is a unit - it is neither prime nor composite. For example, the integer 14 is a composite number because it can be factored as 2 × 7.

Composite. It is divisible by 3 for any n.

Are you asking is 525 prime? The a nswer is no. It is a composite number. Are you aski ng what is the prime factorizatio n of 525? Prime factorizatio n of 525 = 3 * 5 * 5 * 7

The easiest, but not the most efficient way, to program this is to take your number "n" and test all the numbers from 2 to n-1 to see if they divide n, if none of them do, then n is prime.

#include<iostream.h> #include<conio.h> int main() { int i,n; clrscr(); cout<<"PROGRAM TO CHECK IF THE NUMBER IS PRIME OR NOT:"<<endl; cout<<"Enter a number:"; cin>>n; for(int i=2;i<n;i++) { if(n%i==0) cout<<"\nTHE NUMBER IS COMPOSITE"<<endl; else cout<<"\nTHE NUMBER IS PRIME"<<endl; } return 0; }

1726 is certainly not a prime number as it is even and n\hewnce divisible by 2 ... a prime number is one that can only be divided by 1 and by itself, nothing else 1726 is then a composite number

No. All integers are divisible by 1 and themselves. Prime numbers are only divisible by 1 and themselves. Since you were not told that only 1 and n divide into n, you do not know if it is prime. Also, if n = 1, it is neither a prime number nor a composite number.

Any number of the form n = a*b*c*d*e*f where a, b, c, d, e and f are different prime numbers. n has 26 = 64 factors in total, of which 1 is the number 1 (neither prime nor composite), 6 are prime, and the remaining 57 are composite.

Nothing. If n is 2, 3n - 1 is 5 and 5 is prime.