4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
6(n - 4)(n + 1) n = 4, -1
It could be any number of your choice. Pick a number and I can find you a quartic (power 4) polynomial which will give the above four and your choice as the first five terms. But the simplest cubic rule is Un = (n3 - 6n2 + 8)/3 for n = 1, 2, 3, ... which gives U5 = 5
It can be any number that you like. Given any position (n) and any number in that position Un, it is a simple matter to find a polynomial of degree 5 that will generate the above 5 numbers as the first five and you selection as the nth. In this case there is a much simpler rule: Un = 6n2 + 5 for n = 1, 2, 3, ...
8 (again) The sequence is generated by t(n) = (-n3 + 6n2 + 7n - 12)/6 for n = 1, 2, 3, ...
2n(3n + 8)
(3m+2n)(m+3n)
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
6n2+6n+1
The chemical equation for the reaction between glucose (C6H12O6) and potassium nitrate (KNO3) is: C6H12O6 + 6KNO3 → 6KOH + 6CO2 + 6N2 + 6H2O.
6n2
6(n - 4)(n + 1) n = 4, -1
It could be any number of your choice. Pick a number and I can find you a quartic (power 4) polynomial which will give the above four and your choice as the first five terms. But the simplest cubic rule is Un = (n3 - 6n2 + 8)/3 for n = 1, 2, 3, ... which gives U5 = 5
The chemical equation for nitroglycerin is 4C3H5N3O9 -> 6N2 + 10H2O + 12CO2 + O2.
-8. The numbers can be generated by the following quadratic: t(n) = -6n2 + 23n - 4 for n = 1, 2, 3, ...
was this answered becuase i need to know too