Neither
Prime if n=1, composite otherwise.
Composite. It is divisible by 3 for any n.
Are you asking is 525 prime? The a nswer is no. It is a composite number. Are you aski ng what is the prime factorizatio n of 525? Prime factorizatio n of 525 = 3 * 5 * 5 * 7
To write a BASIC program that checks if an input number is prime or composite, you can use a loop to test divisibility. First, prompt the user for a number and then check if it's less than 2 (which is neither prime nor composite). For numbers greater than 1, iterate from 2 to the square root of the number, checking if it divides evenly (using the modulus operator). If you find a divisor, the number is composite; otherwise, it's prime. Here's a simple example: INPUT "Enter a number: ", N IF N < 2 THEN PRINT "Neither prime nor composite": END IS_PRIME = TRUE FOR I = 2 TO SQR(N) IF N MOD I = 0 THEN IS_PRIME = FALSE EXIT FOR END IF NEXT I IF IS_PRIME THEN PRINT N; " is prime" ELSE PRINT N; " is composite"
No, if you think that you have it, you can always find one that is larger. Take, for example you find an even composite number (all even numbers, except 2 - which is the only even prime, are composite). Call this number N. Now add 2 to N for N+2, which is also even, so it is also a composite. What about odd composites: if you find an odd composite(M), then add 1 to it: odd+odd=even, so M+1 is even, which is also composite. You can keep going forever.
Prime if n=1, composite otherwise.
2 is a prime number. 2 times anything but 1 is composite.
A composite number is a positive integer which has a positive divisor other than one or itself. In other words, if 0 < n is an integer and there are integers 1 < a, b < n such that n = a × b then n is composite. By definition, every integer greater than one is either a prime number or a composite number. The number one is a unit - it is neither prime nor composite. For example, the integer 14 is a composite number because it can be factored as 2 × 7.
It is one
Composite. It is divisible by 3 for any n.
Are you asking is 525 prime? The a nswer is no. It is a composite number. Are you aski ng what is the prime factorizatio n of 525? Prime factorizatio n of 525 = 3 * 5 * 5 * 7
The easiest, but not the most efficient way, to program this is to take your number "n" and test all the numbers from 2 to n-1 to see if they divide n, if none of them do, then n is prime.
#include<iostream.h> #include<conio.h> int main() { int i,n; clrscr(); cout<<"PROGRAM TO CHECK IF THE NUMBER IS PRIME OR NOT:"<<endl; cout<<"Enter a number:"; cin>>n; for(int i=2;i<n;i++) { if(n%i==0) cout<<"\nTHE NUMBER IS COMPOSITE"<<endl; else cout<<"\nTHE NUMBER IS PRIME"<<endl; } return 0; }
1726 is certainly not a prime number as it is even and n\hewnce divisible by 2 ... a prime number is one that can only be divided by 1 and by itself, nothing else 1726 is then a composite number
Any number of the form n = a*b*c*d*e*f where a, b, c, d, e and f are different prime numbers. n has 26 = 64 factors in total, of which 1 is the number 1 (neither prime nor composite), 6 are prime, and the remaining 57 are composite.
No. All integers are divisible by 1 and themselves. Prime numbers are only divisible by 1 and themselves. Since you were not told that only 1 and n divide into n, you do not know if it is prime. Also, if n = 1, it is neither a prime number nor a composite number.
#include<stdio.h> #include<conio.h> void main() { clrscr(); int n,i,np=0;//np is boolean operator (true/false) printf("\n Enter a number :"); scanf("%d",&n); for(i=2;i<=(n-1);i++) /*we know that a number which is divisible by 1 and divisible by itself Is A PRIME NUMBER. So no need to check n divisible by 1 and divisible by itself */ { if(n%i==0) { np=1; break; //come out of for loop } } if(np==1) // in if statement np=1 ,it confirms that number is composite. { printf("Sorry,its composite number %d",n); } else { printf("it is a prime number %d",n); } OUTPUT: Enter a Number: 12 Sorry its a composite number 12 Enter a number 17 it is a prime number 17