No, it is not.
65/67/69
Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.
189/3 = 63 So the three odd integers are 61, 63 and 65
-1
There is no set of three consecutive integers for 106.
Start with "-3", then add one at a time to get as many consecutive integers as you want.
The 3 consecutive odd positive integers are 7, 9 and 11.
One possible answer is -4 and -3.
This would mean that the average of the three numbers would be 189 / 3 = 63.Therefore the three numbers you are looking for are 61 + 63 + 65.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
greater