No, it is not.
65/67/69
Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.
189/3 = 63 So the three odd integers are 61, 63 and 65
-1
The product of two consecutive integers can be represented mathematically as ( n(n + 1) ), where ( n ) is any integer. This expression captures the idea that the two integers are ( n ) and ( n + 1 ). For example, if ( n = 3 ), the product would be ( 3 \times 4 = 12 ). This representation highlights the relationship between consecutive numbers in a simple algebraic form.
There is no set of three consecutive integers for 106.
Consecutive negative integers that sum to 440 would be integers that are sequentially negative and add up to that positive number. For example, the integers -1, -2, -3, and so forth are negative integers, but their sum cannot reach 440 since they are all negative. If you meant the consecutive negative integers that multiply to give -440, those could be -20 and -22, as they are consecutive and their product is 440.
The 3 consecutive odd positive integers are 7, 9 and 11.
This would mean that the average of the three numbers would be 189 / 3 = 63.Therefore the three numbers you are looking for are 61 + 63 + 65.
Start with "-3", then add one at a time to get as many consecutive integers as you want.
One possible answer is -4 and -3.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.