Yes. The result is 142.
58,930 is divisible by these factors: 1, 2, 5, 10, 71, 83, 142, 166, 355, 415, 710, 830, 5893, 11786, 29465, 58930.
Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES
There are 3725 of them because 3725/5 = (35+710) => 745
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
58,930 is divisible by these factors: 1, 2, 5, 10, 71, 83, 142, 166, 355, 415, 710, 830, 5893, 11786, 29465, 58930.
Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES
The factors of 710 are: 1, 2, 5, 10, 71, 142, 355, 710.
The factors of 710 are 1, 2, 5, 10, 71, 142, 355, and 710. The prime factors of 710 are 2 x 5 x 71.
2 x 5 x 71 = 710
1, 2, 5, 10, 71, 142, 355, 710.
There are 3725 of them because 3725/5 = (35+710) => 745
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.