58,930 is divisible by these factors: 1, 2, 5, 10, 71, 83, 142, 166, 355, 415, 710, 830, 5893, 11786, 29465, 58930.
Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES
There are 3725 of them because 3725/5 = (35+710) => 745
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
58,930 is divisible by these factors: 1, 2, 5, 10, 71, 83, 142, 166, 355, 415, 710, 830, 5893, 11786, 29465, 58930.
Check your divisibility rules: 2: One's digit is an even number YES 3: The sum of the digits is divisible by 3 NO: 7 + 1 + 0 = 8 which is not divisible by 3 5: One's digit is a 5 or a 0 YES 9: The sum of the digits is divisible by 9 NO: 7 + 1 + 0 = 8 which is not divisible by 9 10: One's digit is a 0 YES
The factors of 710 are 1, 2, 5, 10, 71, 142, 355, and 710. The prime factors of 710 are 2 x 5 x 71.
The factors of 710 are: 1, 2, 5, 10, 71, 142, 355, 710.
2 x 5 x 71 = 710
1, 2, 5, 10, 71, 142, 355, 710.
There are 3725 of them because 3725/5 = (35+710) => 745
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.