Yes: 810 / 10 = 81
Any element of the set of numbers of the form 2345690*k where k is an integer is evenly divisible.
810 is divisible by 10, so it is already at the nearest 10.
810/2 = 405 810/3 = 270 * 810/4 = 202.5 810/5 = 162 810/6 = 135 810/9 = 90 810/10 = 81 so 810 is divisible by 2 3 5 6 9 10 but not by 4
No, but I suspect you want to know if 810 is divisible by those numbers. Out of that group, 810 is divisible by 2, 3, 5, 6, 9 and 10
All but 4.
810 is divisible by 2, 4
810 is divisible by 3. No need to do anything to it.
Yes. 810 is divisible by these numbers: 1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 81, 90, 135, 162, 270, 405, 810.
no
Clearly, both 810 and 910 are divisible by 5. A wee trick regarding numbers that are a multiple of 3, is that the component numbers, when added together, are divisible by three. So, 654 is divisible by 3, as 6+5+4 = 15 which is divisible by 3. In your example, 810 components add up to 9, which is divisible by 3. But the components of 910 add up to 10 which is not so divisible.
No