Heck no 9 is not a muiltiple of five like 5 10 15 20 are so no
The largest 5-digit number divisible exactly by 99 is 99990.
From 10 to 99 (inclusive) there are 90 numbers.18 are evenly divisible by 5.Therefore 72 are not.
891/ 9 = 99 so it is divisible 891/ 5 = 178.2 so it is not divisible (not by a whole number anyway)
All multiples of 99 are divisible by 99
99990 ----------------------------------------------------------------------------------------------- Largest 5 digit number is 99999 99999 ÷ 99 = 1010 r 9 → largest 5 digit number divisible by 99 is 99 x 1010 = 99990
99
-94
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.
99 is divisible by 1, 3, 9, 11, 33, and 99.
There are 17,999 such numbers.
No.
No, it is not.