Heck no 9 is not a muiltiple of five like 5 10 15 20 are so no
The largest 5-digit number divisible exactly by 99 is 99990.
From 10 to 99 (inclusive) there are 90 numbers.18 are evenly divisible by 5.Therefore 72 are not.
All multiples of 99 are divisible by 99
891/ 9 = 99 so it is divisible 891/ 5 = 178.2 so it is not divisible (not by a whole number anyway)
99990 ----------------------------------------------------------------------------------------------- Largest 5 digit number is 99999 99999 ÷ 99 = 1010 r 9 → largest 5 digit number divisible by 99 is 99 x 1010 = 99990
99
-94
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.
99 is divisible by 1, 3, 9, 11, 33, and 99.
There are 17,999 such numbers.
No, it is not.
No.