No - 9/0 is an impermissible number. The denominator can't be a zero.
Digit is not a real number unless it is 0-9
0 to 9 are the real numbers.
It is a negative mixed fraction or improper fraction, a rational number, a real number.
-9 + 9 = 0 The equation can be written 9 - 9 = 0 The answer is 0 (zero)
9
9 + x = 0 x = -9 Hence 9 - 9 = 0
The answer is 0.
(9+9+9+9)/9 + (9-9) + (9-9) = 36/9 + 0 + 0 = 4 + 0 + 0 = 4
There may be some hidden agenda in this question. Why would 9 not be a real number?
Adding zero to any number results in the original number, so 9 + 0 = 9.
7 over 9... I would think it would be 0 and 7/9. If the top number is more than the denominator, it's hard to get a mixed fraction.
It is not a real number.