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What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
What is a slope of 0?
A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
How do you find the slope of a given equation?
Slope= Y2-Y1 over X2-X1.for example the slope of the points (2,2) & (1,0) m=y2-y1 over x2-x1 =0-2 over 1-2 =-2/-1 =2
What is the slope of 0 0 and 0 -5?
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate note though, the slope of a horizontal line is 0.
What is the slope of the line that passes through these points 3-0 8-0?
The slope is zero.
