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Q: Is The slope on a position-time graph is representative of the acceleration of the object?

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The acceleration of an object.

This means that it has a constant acceleration. It DOES NOT mean that the object is at rest.

The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).

acceleration

The slope of the speed/time graph is the magnitude (size) of the object's acceleration.

The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.

The graph of force versus acceleration tells us that there is a direct relationship between the force applied to an object and the amount of acceleration that object experiences. More force applied, more acceleration, and much more force applied yields much more acceleration.

acceleration.

With a straight line.

A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.

The slope (gradient) of a speed v time graph is acceleration. If the graph is a straight line, then the acceleration is constant. if the slope is 0 (ie the line is horizontal) then the acceleration is 0, and the object is moving with a constant speed (which can be 0, ie the object is stationary). If the graph is "slanted" then depending upon which way the line is "slanted" the object is accelerating or decelerating (the steepness of the slope gives the rate of this). So the object is moving with constant acceleration and either speeding up or slowing down - which, and by how much, depends upon the gradient of the graph.

Acceleration is negative when the object is moving in the opposite direction. on a graph the line would be in the negative quadrant.

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