Yes.
Yes, always. That is the definition of a rational number.
Because that is how a rational number is defined!
Because that is how a rational number is defined!
A rational number is always the result of dividing an integer when the divisor is nonzero.
Yes, it is.
Yes.
Yes, by definition.
I had this name question for homework :| no
Actually the product of a nonzero rational number and another rational number will always be rational.The product of a nonzero rational number and an IRrational number will always be irrational. (You have to include the "nonzero" caveat because zero times an irrational number is zero, which is rational)
Divide a non-zero integer by a non-zero integer.
If ( p ) is an integer and ( q ) is a nonzero integer, then the expression ( \frac{p}{q} ) will always yield a rational number. Additionally, since ( q ) is nonzero, ( p ) cannot be divided by zero, ensuring the division is valid. Furthermore, ( p + q ) will also be an integer, as the sum of two integers is always an integer.
Integer, a real number and a rational number.