"If a number is an integer, then it is a whole number." In math terms, the converse of p-->q is q-->p. Note that although the statement in the problem is true, the converse that I just stated is not necessarily true.
A rational number is any number of the form p/q where p and q are integers and q is not zero. If p and q are co=prime, then p/q will be rational but will not be an integer.
Assuming that you mean not (p or q) if and only if P ~(PVQ)--> P so now construct a truth table, (just place it vertical since i cannot place it vertical through here.) P True True False False Q True False True False (PVQ) True True True False ~(PVQ) False False False True ~(PVQ)-->P True True True False if it's ~(P^Q) -->P then it's, P True True False False Q True False True False (P^Q) True False False False ~(P^Q) False True True True ~(P^Q)-->P True True False False
If ( p ) is an integer between 1000 and 1030, it can be expressed as ( p = 1000 + n ), where ( n ) ranges from 0 to 30. The sum of the digits of ( p ) is given by ( 1 + \text{(sum of the digits of } n) ). Since 1 is odd, for the total sum of the digits to be odd, the sum of the digits of ( n ) must be even. As a result, if ( p ) is odd, ( n ) must be odd (e.g., 1, 3, 5, etc.), confirming that ( p ) is indeed odd. Thus, the statement is true: if the sum of the digits of ( p ) is odd, then ( p ) must be odd.
A counter example is a disproving of an answer. The counterexample to this is basically your saying if you have two nonzero digits in the tenths place and subtract it, you'll always get a nonzero digit in the answer. but if you have 560.4 - 430.4, then you'll get 130.0. there is a zero in the tenths place. I just disproved that you will always get a nonzero digit in the tenths place. 4 - 4 = 0. the 4s represent the tenths place in each of the 4s in the problem. walah. :P
Then p/q is a rational number.
if p is an integer and q is a nonzero integer
Any fraction p/q where p is an integer and q is a non-zero integer is rational.
Any fraction p/q where p is an integer and q is a non-zero integer is rational.
"If a number is an integer, then it is a whole number." In math terms, the converse of p-->q is q-->p. Note that although the statement in the problem is true, the converse that I just stated is not necessarily true.
8 is an integer, which, by definition, are not irrational. In particular, an irrational number is a number that cannot be written in the form p/q for p and q both integers. However, since 8 clearly is equal to 8k/k for any integer k (and for that matter any nonzero number k), 8 is not irrational
It is ~p.
S-P interval means the integer minus the integer. The difference times nine.
The truth values.
A rational number is any number of the form p/q where p and q are integers and q is not zero. If p and q are co=prime, then p/q will be rational but will not be an integer.
There is big deal. x and y are commonly used as variables, p and q are used a statements in logic.
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q