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"If a number is an integer, then it is a whole number." In math terms, the converse of p-->q is q-->p. Note that although the statement in the problem is true, the converse that I just stated is not necessarily true.
A rational number is any number of the form p/q where p and q are integers and q is not zero. If p and q are co=prime, then p/q will be rational but will not be an integer.
Assuming that you mean not (p or q) if and only if P ~(PVQ)--> P so now construct a truth table, (just place it vertical since i cannot place it vertical through here.) P True True False False Q True False True False (PVQ) True True True False ~(PVQ) False False False True ~(PVQ)-->P True True True False if it's ~(P^Q) -->P then it's, P True True False False Q True False True False (P^Q) True False False False ~(P^Q) False True True True ~(P^Q)-->P True True False False
A counter example is a disproving of an answer. The counterexample to this is basically your saying if you have two nonzero digits in the tenths place and subtract it, you'll always get a nonzero digit in the answer. but if you have 560.4 - 430.4, then you'll get 130.0. there is a zero in the tenths place. I just disproved that you will always get a nonzero digit in the tenths place. 4 - 4 = 0. the 4s represent the tenths place in each of the 4s in the problem. walah. :P
It in Math, (Geometry) If p implies q is a true conditional statement and not q is true, then not p is true.
Then p/q is a rational number.
if p is an integer and q is a nonzero integer
Any fraction p/q where p is an integer and q is a non-zero integer is rational.
Any fraction p/q where p is an integer and q is a non-zero integer is rational.
"If a number is an integer, then it is a whole number." In math terms, the converse of p-->q is q-->p. Note that although the statement in the problem is true, the converse that I just stated is not necessarily true.
8 is an integer, which, by definition, are not irrational. In particular, an irrational number is a number that cannot be written in the form p/q for p and q both integers. However, since 8 clearly is equal to 8k/k for any integer k (and for that matter any nonzero number k), 8 is not irrational
It is ~p.
S-P interval means the integer minus the integer. The difference times nine.
Yes - see below. (But the reverse is not true). p is rational so p = x/y where x and y are integers. x is an integer so x*x is an integer, and y is an integer so y*y is an integer. So p2 = (x/y)2 = x2/y2 is a ratio of two integers and so is rational.
The truth values.
A rational number is any number of the form p/q where p and q are integers and q is not zero. If p and q are co=prime, then p/q will be rational but will not be an integer.
Let us consider "This statement is false." This quotation could also be read as "This, which is a statement, is false," which could by extent be read as "This is a statement and it is false." Let's call this quotation P. The statement that P is a statement will be called Q. If S, then R and S equals R; therefore, if Q, then P equals not-P (since it equals Q and not-P). Since P cannot equal not-P, we know that Q is false. Since Q is false, P is not a statement. Since P says that it is a statement, which is false, P itself is false. Note that being false does not make P a statement; all things that are statements are true or false, but it is not necessarily true that all things that are true or false are statements. In summary: "this statement is false" is false because it says it's a statement but it isn't.