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no, it's the commutative property of addition.

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Q: Is a plus b equals b plus a additive indentity?
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Related questions

If a plus b equals 0 what can you say about the component?

That a and b are additive inverses of one another.


How -A multiplied by -B equals plus AB was determined and when?

A*(B-B) = A*0 = 0 Expanding the left hand side, using the distributive property, A*B + A*(-B) = 0 That is, A*B and A*(-B) are additive inverses. Next, (A-A)*(-B) = 0*(-B) = 0 Expanding, A*(-B) + (-A)*(-B) = 0 Therefore A*(-B) and (-A)*(-B) are additive inverses But, from above, the additive inverse of -A*B is A*B Therefore (-A)*(-B) = A*B It is not known when this was proven.


How can you prove if a and b are real numbers then a plus b-a equals b?

Real numbers are commutative under addition (and subtraction) so a + b - a = a - a + b The set of Real numbers includes an additive identity, 0, such that a - a = 0 so a - a + b = 0 + b The additive identity also has the property that 0 + b = b [= b + 0] so 0 + b = b


If a plus b equals c and b plus c equals d and c plus d equals e and a equals 7 and e equals 5 what is a plus b plus c plus d plus e equal?

the answer is a


What is b plus b plus b plus b equals?

4b


CAN 0 plus equals B plus equals B?

Yes because if 1+0=1 than 0 plus b equals b


If a plus b equals 40 b plus c equals 34 and a plus c equals 42 what does b equal?

a=24 b=16 c=18


If a plus b plus c not equal to 0 then a divided by b plus c equals b divided by c plus a equals c divided by a plus b prove that a equals b equals c?

Because there is no way to define the divisors, the equations cannot be evaluated.


If a plus a equals b and b plus c equals a and a-c equals b what is c?

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)


If a plus b equals c then c - b equals?

A.


What is a plus b equals to?

a+b=a+b


A plus b plus c equals 180 b equals 3a c equals 5a?

a = 20 b = 60 c = 100