A*(B-B) = A*0 = 0
Expanding the left hand side, using the distributive property, A*B + A*(-B) = 0
That is, A*B and A*(-B) are additive inverses.
Next,
(A-A)*(-B) = 0*(-B) = 0
Expanding, A*(-B) + (-A)*(-B) = 0
Therefore A*(-B) and (-A)*(-B) are additive inverses
But, from above, the additive inverse of -A*B is A*B
Therefore (-A)*(-B) = A*B
It is not known when this was proven.
yes because ab plus bc is ac
Commutativity.
The existence of the additive inverse (of ab).
associative property
the midpoint of AB.
C minus B equals AB
ab=1a+1b a is equal to either 0 or two, and b is equal to a
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
No, A+B is left as A+B AB would be A x B
NM equals 2x + 1, as stated in the question!
An exothermic chemical reaction.
If you do not assume that "plus" is commutative, all that can be said that it is equal to A plus B.