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No, 9 is divisible by 3 and 9, but not six

3 x 9 = 27, also not divisible by 6

Q: Is every number divisible by 3 and 9 is also divisible by 6 is this true?

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Yes

Yes, it's true. 3 is one of the factors of 6, so any number that has six as a factor also has 3 as a factor.

If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.

Yes. Every number is divisible by itself or 1.

If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.

Yes, that is true.

Not always because 33 is divisible by 3 but not by 9

False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.

True. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.

Being divisible by 4, means that it will also be divisible by 2, so that doesn't tell you anything about divisibility by 8. But if you divide the number by 2, and this quotient is divisible by 4, then yes the original number is divisible by 8.

A number that is divisible by 2 is not always evenly divisible by 6. It must also be divisible by 3, and must not be smaller than 6. The numbers 2, 4, 8, 10, 14, 16, 20, 22, 26, and 28 etc. are all divisible by 2 but not (evenly) by 6. The opposite is true, though. Any number divisible by 6 is also divisible by 2.

True fact.