Wiki User
∙ 6y agoThe LCM will never be less than the GCF of a set of numbers.
Wiki User
∙ 6y agoThe LCM of two numbers will never be less than the GCF.
The LCM of a set of numbers will never be less than the GCF.
The LCM of a set of numbers will never be less than the GCF.
When their GCF is greater than one.
If their GCF is 1, their LCM is their product. If their GCF is greater than 1, their LCM is less than their product.
The pair of numbers whose GCF is 1 and LCM is 36 is 9 and 4. The numbers should be greater than their GCF and less than their LCM.
GCF - Greatest Common Factor (GCF is always smaller or equal to at least one of the numbers) LCM - Least Common Multiple (LCM is always greater or equal to at least one of the numbers)
No.The gcf of two numbers is LESS THAN OR EQUAL than their lcm.The gcf of two DIFFERENT numbes is LESS THAN their lcm.
If the GCF of two numbers is 1, their LCM will be their product. Such numbers are called relatively prime, or co-prime. Any two prime numbers (like 3 and 5) will be that way, but the numbers don't have to be prime (like 4 and 9).
The LCM will never be less than the GCF. To be a multiple of both numbers, the LCM will have to be equal to or greater than the larger number. To be a factor of both numbers, the GCF will have to be equal to or less than the smaller number. The only problem comes when you're comparing a number to itself. The LCM of 10 and 10 is 10. The GCF of 10 and 10 is 10.
The pair of numbers whose GCF is 1 and LCM is 36 is 9 and 4. The numbers should be greater than their GCF and less than their LCM.
There cannot be any such numbers. Suppose you have the numbers X and Y, and without loss of generality, assume that X ≤ Y. Then GCF(X, Y) is a factor of X and of Y. Therefore, GCF ≤ X which is ≤ Y also LCM(X, Y) is a multiple of X and of Y. Therefore, LCM ≥ Y which is ≥ X Combining the inequalities gives GCF ≤ X ≤ Y ≤ LCM and so GCF ≤ LCM. That is, the GCF cannot possibly be greater than LCM.