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How do you find vertical and horizontal components when given the initial velocity?
Wiki User
∙ 11y ago
If the initial velocity is v, at an angle x to the horizontal, then
the vertical component is v*sin(x) and the horizontal component is v*cos(x).
Wiki User
∙ 11y ago
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Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
Can the effect of initial velocity on final velocity be predicted?
Well, (final velocity) = (initial velocity) + (acceleration x time)
What is the formula for calculating final velocity when you know the initial speed and the acceleration?
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to the product to find the final velocity.
The horizontal and vertical components of the initial velocity of a tennis ball are 18.2 ms and 21.3 ms respectively what is the magnitude of the initial velocity of the ball?
To take the magnitude of the velocity you will need to square both the horizontal and vertical components and then take the square root of their sum. So: V=(Vx2+Vy2)1/2
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
How is the horizontal component of velocity for a projectile affected by the vertical component?
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
An aeroplane flying at a constant velocity releases a bomb. As the bomb drops down from the aeroplane what will be the position of the bomb with respect to the plane?
There are two forces on the bomb when it is dropped; horizontal, and vertical. The vertical force is gravity, and the horizontal force is the velocity of the plane when the bomb is dropped. In order to determine how far away the bomb will drop from the initial point of release, it is necessary to know the height that the plane is at, and the velocity of the plane, which is also the initial horizontal velocity of the bomb (it is constant, neglecting air resistence.)
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
A rookie quarterback throws a football with an initial upward velocity component of 16.7 and a horizontal velocity component of 20.2 Ignore air resistance?
The initial velocity of the football can be easily found by solving for the magnitude of the vector formed by adding the two components given. This is accomplished using the Pythagorean theorem. The initial velocity of the football is approximately 26.2 m/s.
How do you draw a horizontal?
It's parabolic. More specifically, it's half a parabola, with a vertex at the point of origin. You see, horizontal and vertical velocity are independent of each other. This means that the projectile will more horizontally at a constant velocity (ignoring wind resistance) equal to its initial velocity. At the same time, the projectile is accelerated downward at a rate of 9.8 m/s2 (approximately). Since it undergoes constant acceleration, it increases in velocity every second exponentially, giving it a parabolic curve. As an interesting side note, since horizontal and vertical velocity are always independent of each other, any velocity (really, any vector) can be represented as its horizontal and vertical components, allowing one to add up the individual components and to find a resultant vector quantity. Here's an example drawing of the curve described: http://www.staff.amu.edu.pl/~romangoc/graphics/M2/1-projectile-motion/M2-3.gif Keep in mind that if the point of origin is at a greater vertical level than the ground, the projectile will fall all the way to the ground, past the horizontal axis.
A guy drove a car from a flat ground on top of a building and laded on the next one that's 100m away several floors down. If the car landed with an angle 30 degrees to x axis, find initial horizontal speed of car?
Initial horizontal velocity = ux (Note this velocity does not affect by gravity so stays the same throughout the jump) Initial vertical velocity = uy = 0 time to travel horizontal distance, t = (horizontal distance)/(horizontal velocity) t = 100/ux This is the same time the car takes to travel vertical distance. Using one of the equation of motion vertical landing velocity, vy = uy + gt vy = 0 + (9.81)(100/ux) vy = 981/ux angle of landing = 30° tan30° = vy/ux tan30° = (981/ux)/ux (ux)² = 981/tan30° ux = 41.22 m/s
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
What are the two types of motion a projectile has?
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
