Study guides

Q: Is it possible to divide a number by 4 and get a remainder of 5?

Write your answer...

Submit

Related questions

assume dividing into whole number if you divide by 4 then remainder will be 0,1,2, or 3 by 6 then remainder will be 0,1,2,3,4 or 5 by 9 then remainder will be 0,1,2,3,4,5,6,7 or 8

58

26. This is because when you divide 26 by 5, you have a remainder of 1, and when you divide it by 4, you have a remainder of 2

20 / 4 = 5 (no remainder) 21 / 4 = 5 remainder 1 22 / 4 = 5 remainder 2 23 / 4 = 5 remainder 3 24 / 4 = 6 (no remainder) Therefore the numbers that can remain after you've divided a number by four are 0, 1, 2, and 3.

If you divide an odd number by 4, you will always have a remainder, either 1 or 3.

24

this does not make sense. What number?

it is 24, 24 divide by five is 4 with a remainder of four. 24 divided by 5= 4 =20 +4= 24

1,2, and 4 will.

Not if you divide correctly.

Divide it by 4 and if you have a remainder of 0, Viola!

Any number of the form 5n+4 where n is an integer.

1, 2, 4 and 8 all divide into 8 without a remainder.

the number is 43:43:7=6 remainder 143:9=4 remainder 743:11=3 remainder 10Also possible: 241, 439, 637, 835, 1033, 1231, 1429, 1627, 1825, 2023, 2221, 2419, 2617, 2815, 3013, 3211, 3013, 3211, 3409, 3607... where number is 198xN+43 and N is positive integer number

The cannot be such a number. The biggest possible remainder is 2.

5 will go into 9 once with a remainder of 4.

4

In division by 5, you can have remainders of 0, 1, 2, 3, and 4. If you count zero, then you can have five possible remainders. If you are not counting zero, then 4 possible remainders.

It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

Each number will divide into 420 with no remainder

When you divide by 5, the remainder can be 0, 1, 2, 3, or 4, but no more than 4.

If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.

26 is one possibility

19.

Since 225 is an odd number, it is impossible to divide it by 4 without leaving a remainder.