In division by 5, you can have remainders of 0, 1, 2, 3, and 4. If you count zero, then you can have five possible remainders. If you are not counting zero, then 4 possible remainders.
Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).
2235
The possible number of remainders is always one less than the divisor.
2465
4, remainder 3
Divide by 36. That tells you how many yards. Divide the remainder by 12. That tells you how many feet. The final remainder tells you the number of inches.
87 is one of infinitely many numbers that meet these requirements.
Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).
Divide the inches by 12 (integer division). The integer result is the number of feet. The remainder is the number of inches.
If the dividend is a positive integer (a whole number) then the possible remainders are 0 (zero) when the dividend is an even number and 1 when the dividend is an odd number.
Sixteen.
2
55
2235
23457 divided by 23456 leaves a remainder of 1, and it is divisible by 7. So that is one of infinitely many possible answers.
Divide by 60 and the remainder is the number off minutes over. 137 divided by 60 is 2 hours 17 minutes
The possible number of remainders is always one less than the divisor.