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How can you tell without solving the equation thatone halfx equal four and seven eight that x is greater than four and seven eight?
Because in any case of 1/2x, you have to multiply the other end of the sum with two. (so 4 7/8 times 2). It has to be more than 4 7/8, ergo: it can not be 7/8
How do you factor 80x2-5?
5x**2-30x-801. Remove common term (and ignore til end):5(x**2-6x-16)2. Multiply first and third terms1*-16=-163. Factor product of first and third terms-16, 1-8, 2-4, 416, -18, -24. Choose factors whose sum is equal to second term-8+2=-65. Rewrite equation using factorsx**2-8x+2x-166. Halve the expressionx**2-8x2x-167. Factor each halfx**2-8x --> x(x-8)2x-16 --> 2(x-8)8. Recombinex(x-8)+2(x-8)9. Factor out common term:(x-8)(x+2)10. Reintroduce part from beginning5(x-8)(x+2)
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