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Probably not, though it is hard to work out the mapping "r equals 1 2"

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Q: Is relation r equals 1 2 on the set a equals 1 2 3 is transitive?

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It is a partially ordered set. That means it is a set with the following properties: a binary relation that is 1. reflexive 2. antisymmetric 3. transitive a totally ordered set has totality which means for every a and b in the set, a< or equal to b or b< or equal to a. Not the case in a poset. So a partial order does NOT have totality.

(1) transitive, (2) reflexive

An equivalence relation r on a set U is a relation that is symmetric (A r Bimplies B r A), reflexive (Ar A) and transitive (A rB and B r C implies Ar C). If these three properties are true for all elements A, B, and C in U, then r is a equivalence relation on U.For example, let U be the set of people that live in exactly 1 house. Let r be the relation on Usuch that A r B means that persons A and B live in the same house. Then ris symmetric since if A lives in the same house as B, then B lives in the same house as A. It is reflexive since A lives in the same house as him or herself. It is transitive, since if A lives in the same house as B, and B lives in the same house as C, then Alives in the same house as C. So among people who live in exactly one house, living together is an equivalence relation.The most well known equivalence relation is the familiar "equals" relationship.

(-2,-1)

No, but it helped.

The conversion between m,mm and dm are given .On finding the relation we get as follows . 1 m =10 dm. 1 m =100 cm. 1 m=1000 mm.

The conversion relation between in and cm are given .By the conversion table the relation we get is as follows. 1 inch =2.54 cm .

Dividing any number by 1 equals the number you started with.

taking an example of matrix x ,we find whether this matrix is transitive or not: x=[1 1 0 ;1 0 1;1 0 1] m=1; for i=1:3 for j=1:3 if x(i,j)==1 for k=1:3 if x(j,k)==1 if x(i,k)~=1 m=0; end end end end end end if m==1 disp('Given matrix is Transitive') else disp('Given Matrix is not Transitive') end

x = 5

S = {-5, 1}

(1) Symmetric, (2) Transitive, (3) HL

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