No, slope and initial value are not the same. The slope refers to the steepness or incline of a line on a graph, whereas the initial value represents the y-coordinate of the point where the line intersects the y-axis.
I suggest: - Take the derivative of the function - Find its initial value, which could be done with the initial value theorem That value is the slope of the original function.
The value of the two is the same. The slope is exactly the same as the steepness if the line goes from bottom-left to top-right and it is the negative value of the steepness if the line goes from top-left to bottom-right.
They both will have the same slope or gradient but with different y intercepts
plotting a slope means plotting a graph of y against x.to get the linear function ,the only thing to do is to know whether the value of y and the equivalent value of x at the point if its a well plotted slope normally any choosen point will be the same .assuming it is not a curve.if not replot.
The slope changes as the value of x changes. For any point x, the slope is -8x.
I suggest: - Take the derivative of the function - Find its initial value, which could be done with the initial value theorem That value is the slope of the original function.
Yes, it is.
By using the rise over run formula: (y2-y1)/(x2-x1) This means you need two points on the line in order to solve for the slope. You take the y-value for the second point and then subtract the y-value from the initial point. Then divide that by the x-value of the second point minus the x-value from the initial point.
If you want to find the initial value of an exponential, which point would you find on the graph?
We suspect that you're also given a line on the graph. If so, then the initial speed is the slope of the line at the initial position. To get the real slope of the line, you need to know the scales of the axes. If the scales aren't the same, then the real slope of the line isn't what it looks like, and has to be calculated by measuring its progress along both axes just after the initial position.
It's the slope of the line, or your a or m depending on how your teachers teach it. y = mx + b where m = slope and b = y-intercept(or initial value) or y = mx + b where m = slope
The value of the two is the same. The slope is exactly the same as the steepness if the line goes from bottom-left to top-right and it is the negative value of the steepness if the line goes from top-left to bottom-right.
The slope of the line. A positive slope shows that the two variables increase or decrease together. A negative slope indicates they move in opposite directions. A slope of 0 indicates that the "dependent" variable has the same, constant, value whatever value the independent variable takes.
Pick any two points in the table. The slope of the line is(change in the y-value from one point to the other)/(change in the x-value from the same point to the other)
The slope is[ (y-value of 'b') - (y-value of 'a') ] / [ (x-value of 'b') - (x-value of 'a') ]
What does it mean if a slope is numerically a higher value than another slope
The same. Parallel lines have the same slope.