The slope is
[ (y-value of 'b') - (y-value of 'a') ] / [ (x-value of 'b') - (x-value of 'a') ]
y=mx+b
Y=mx+b
6
if line's A and B are perpendicular to each other, the slope of A = -1/(the slope of B)
y= mx + b where m is the slope and b is the y-intercept if by "points" you mean (1,-2)... a slope of -4 means that for every change of 4 in the x direction, there is only a change of 1 in the y direction the line will cross the y axis at -2.25 (there will be a another point a (-3, -3) y = -4x + -2.25
y=mx+b
Y=mx+b
7
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
To find the y-intercept of a line with a given slope and a point it passes through, you can use the slope-intercept form of a line, which is (y = mx + b), where (m) is the slope and (b) is the y-intercept. Substitute the coordinates of the given point and the slope into the equation to solve for (b). Rearranging the equation will yield the value of the y-intercept. Without specific numerical values for the slope and point, I can't provide a numerical answer, but this is the method to find it.
6
y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10
If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
To determine the equations that represent a line, you typically need either the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, or the point-slope form (y - y₁ = m(x - x₁)), where (x₁, y₁) is a point on the line. Additionally, the standard form of a line (Ax + By = C) can also represent a line, where A, B, and C are constants. To identify specific equations, you would need additional information, such as points through which the line passes or its slope.
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
The equation of a line can be expressed in the slope-intercept form, which is ( y = mx + b ), where ( m ) is the gradient and ( b ) is the y-intercept. Given a gradient of -3 and that the line passes through the origin (0,0), the y-intercept ( b ) is 0. Thus, the equation of the line is ( y = -3x ).