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How do you find the slope of the line which passes through the points with coordinates?
y=mx+b
A line passes through the point and has a slope of Write an equation for this line?
Y=mx+b
What is the equation of a horizontal line that passes through the point (3 -3)?
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What is the formula for slope of a perpendicular line?
if line's A and B are perpendicular to each other, the slope of A = -1/(the slope of B)
What is the slope-intercept form of the line that passes through the points 1 and -2 with the slope -4?
y= mx + b where m is the slope and b is the y-intercept if by "points" you mean (1,-2)... a slope of -4 means that for every change of 4 in the x direction, there is only a change of 1 in the y direction the line will cross the y axis at -2.25 (there will be a another point a (-3, -3) y = -4x + -2.25
How do you find the slope of the line which passes through the points with coordinates?
y=mx+b
A line passes through the point and has a slope of Write an equation for this line?
Y=mx+b
How do you Graph a line with a slope passing through the point 4-3?
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Find the slope of the line that passes through the points A(-2, -1) B(3, 5)?
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
What is the equation of a horizontal line that passes through the point (3 -3)?
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What is the equation of a line that passes through the point 3 -4 and has a slope of 2?
y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10
What is the equation of the line written in standard form that passes through the point?
If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b
What is point slope form of an equation of a line?
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
How do you write an equation of a line that passes through the xintercep and yintercept?
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
What is an equation of the line with slope -3 that passes through 2 and 4?
Do you mean (2,4)? If so you plug the number into this equation y=mx+by=-3x+b 4=-6+b b=10 Y=-3x+10 this is your answer
What is the formula for slope of a perpendicular line?
if line's A and B are perpendicular to each other, the slope of A = -1/(the slope of B)
What is the equation of the line that passes through 0 and 3 and has a slope -1?
We can arrange this into point-slope form, thus, we have y - b = s(x - a). By subsituting these values (slope is "s", and the ordered pair is (a, b)), we have:y - 3 = -(x - 0)y = -x + 3y-intercept: 3x-intercept: 3
