y=mx+b
Y=mx+b
6
if line's A and B are perpendicular to each other, the slope of A = -1/(the slope of B)
y= mx + b where m is the slope and b is the y-intercept if by "points" you mean (1,-2)... a slope of -4 means that for every change of 4 in the x direction, there is only a change of 1 in the y direction the line will cross the y axis at -2.25 (there will be a another point a (-3, -3) y = -4x + -2.25
y=mx+b
Y=mx+b
7
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
6
y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10
If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
Do you mean (2,4)? If so you plug the number into this equation y=mx+by=-3x+b 4=-6+b b=10 Y=-3x+10 this is your answer
We can arrange this into point-slope form, thus, we have y - b = s(x - a). By subsituting these values (slope is "s", and the ordered pair is (a, b)), we have:y - 3 = -(x - 0)y = -x + 3y-intercept: 3x-intercept: 3
if line's A and B are perpendicular to each other, the slope of A = -1/(the slope of B)