The slope is
[ (y-value of 'b') - (y-value of 'a') ] / [ (x-value of 'b') - (x-value of 'a') ]
y=mx+b
Y=mx+b
6
if line's A and B are perpendicular to each other, the slope of A = -1/(the slope of B)
y= mx + b where m is the slope and b is the y-intercept if by "points" you mean (1,-2)... a slope of -4 means that for every change of 4 in the x direction, there is only a change of 1 in the y direction the line will cross the y axis at -2.25 (there will be a another point a (-3, -3) y = -4x + -2.25
To find the slope of the line that passes through the points ((a-b)) and ((-a-b)), we first clarify that these points are actually ((a, -b)) and ((-a, -b)). The slope (m) is calculated using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{-b - (-b)}{-a - a} = \frac{0}{-2a} = 0). Thus, the slope of the line is 0, indicating a horizontal line.
y=mx+b
Y=mx+b
7
To find the equation of a line with a slope of 2 that passes through the point (0, 3), you can use the slope-intercept form of a line, which is ( y = mx + b ). Here, ( m ) is the slope and ( b ) is the y-intercept. Since the point (0, 3) indicates that the y-intercept ( b ) is 3, the equation of the line is ( y = 2x + 3 ).
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
To find the y-intercept of a line with a given slope and a point it passes through, you can use the slope-intercept form of a line, which is (y = mx + b), where (m) is the slope and (b) is the y-intercept. Substitute the coordinates of the given point and the slope into the equation to solve for (b). Rearranging the equation will yield the value of the y-intercept. Without specific numerical values for the slope and point, I can't provide a numerical answer, but this is the method to find it.
6
y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b
To determine the equations that represent a line, you typically need either the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, or the point-slope form (y - y₁ = m(x - x₁)), where (x₁, y₁) is a point on the line. Additionally, the standard form of a line (Ax + By = C) can also represent a line, where A, B, and C are constants. To identify specific equations, you would need additional information, such as points through which the line passes or its slope.