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The slope is

[ (y-value of 'b') - (y-value of 'a') ] / [ (x-value of 'b') - (x-value of 'a') ]

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12y ago

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What is the slope of the line that passes through (a-b) (-a-b)?

To find the slope of the line that passes through the points ((a-b)) and ((-a-b)), we first clarify that these points are actually ((a, -b)) and ((-a, -b)). The slope (m) is calculated using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{-b - (-b)}{-a - a} = \frac{0}{-2a} = 0). Thus, the slope of the line is 0, indicating a horizontal line.


How do you find the slope of the line which passes through the points with coordinates?

y=mx+b


A line passes through the point and has a slope of Write an equation for this line?

Y=mx+b


How do you Graph a line with a slope passing through the point 4-3?

7


Which equation represents the line whose slope is 2 and that passes through point (0 3)?

To find the equation of a line with a slope of 2 that passes through the point (0, 3), you can use the slope-intercept form of a line, which is ( y = mx + b ). Here, ( m ) is the slope and ( b ) is the y-intercept. Since the point (0, 3) indicates that the y-intercept ( b ) is 3, the equation of the line is ( y = 2x + 3 ).


Find the slope of the line that passes through the points A(-2, -1) B(3, 5)?

The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.


If A line has a slope of mc012-1.jpg and passes through point mc012-2.jpg. What is the value of the y-intercept?

To find the y-intercept of a line with a given slope and a point it passes through, you can use the slope-intercept form of a line, which is (y = mx + b), where (m) is the slope and (b) is the y-intercept. Substitute the coordinates of the given point and the slope into the equation to solve for (b). Rearranging the equation will yield the value of the y-intercept. Without specific numerical values for the slope and point, I can't provide a numerical answer, but this is the method to find it.


What is the equation of a horizontal line that passes through the point (3 -3)?

6


What is the equation of a line that passes through the point 3 -4 and has a slope of 2?

y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10


What is the slope intercept form of the equation for the line that passes through the point (-10-6) and has a slope of -1?

The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).


What is the equation of the line written in standard form that passes through the point?

If the point is (a, b), and the desired slope is m, the equation is:y - b = m(x - a) If the slope is not given, you can make up any slope. If you add "b" on both sides, you would get: y = m(x-a) + b


Which equations represent the line?

To determine the equations that represent a line, you typically need either the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, or the point-slope form (y - y₁ = m(x - x₁)), where (x₁, y₁) is a point on the line. Additionally, the standard form of a line (Ax + By = C) can also represent a line, where A, B, and C are constants. To identify specific equations, you would need additional information, such as points through which the line passes or its slope.