No.
No, the perpendicular bisector of a side of a triangle does not necessarily pass through the opposite vertex. The perpendicular bisector is a line that is perpendicular to a segment at its midpoint, and it may intersect the interior or exterior of the triangle, depending on its shape. In fact, the only time a perpendicular bisector passes through the opposite vertex is in the case of an isosceles triangle, where the two sides are equal, and their perpendicular bisectors coincide with the altitude.
any isosceles triangle
A circle itself does not form a perpendicular bisector because a perpendicular bisector is a line that divides a segment into two equal parts at a right angle, typically associated with straight segments. However, the concept of a perpendicular bisector can be applied to chords within a circle. The perpendicular bisector of a chord will always pass through the center of the circle.
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.
No, the perpendicular bisector of a side of a triangle does not necessarily pass through the opposite vertex. The perpendicular bisector is a line that is perpendicular to a segment at its midpoint, and it may intersect the interior or exterior of the triangle, depending on its shape. In fact, the only time a perpendicular bisector passes through the opposite vertex is in the case of an isosceles triangle, where the two sides are equal, and their perpendicular bisectors coincide with the altitude.
any isosceles triangle
thank goodness for my math teacher, norm! he said only in an isosceles triangle. The bisector of the vertex angle of an isosceles triangle is perpendicular to the base! =)
iscoceles triangle! =)
Not always because a perpendicular bisector can be constructed with compasses
Not sure what an "irie" is. But a bisector does not need to be perpendicular.
A circle itself does not form a perpendicular bisector because a perpendicular bisector is a line that divides a segment into two equal parts at a right angle, typically associated with straight segments. However, the concept of a perpendicular bisector can be applied to chords within a circle. The perpendicular bisector of a chord will always pass through the center of the circle.
Well, isn't that a happy little question! The altitude of a triangle is always perpendicular to the base it intersects. It's like a little friend that helps the triangle stand tall and proud. Just remember, in the world of triangles, altitudes are always there to lend a hand and make everything more balanced and beautiful.
yes
always
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
An altitude in a triangle is always perpendicular to the opposite side. By definition, an altitude is a line segment from a vertex to the line containing the opposite side, forming a right angle with that side. This property holds true for all types of triangles, including acute, right, and obtuse triangles.